RANK
Let's assume we want to assign a sequential order, or rank, to people within a department based on salary, we might use the
RANK
function like.
SELECT empno,
deptno,
sal,
RANK() OVER (PARTITION BY deptno ORDER BY sal) "rank"
FROM emp;
EMPNO DEPTNO SAL rank
---------- ---------- ---------- ----------
7934 10 1300 1
7782 10 2450 2
7839 10 5000 3
7369 20 800 1
7876 20 1100 2
7566 20 2975 3
7788 20 3000 4
7902 20 3000 4
7900 30 950 1
7654 30 1250 2
7521 30 1250 2
7844 30 1500 4
7499 30 1600 5
7698 30 2850 6
What we see here is where two people have the same salary they are
assigned the same rank. When multiple rows share the same rank the
next rank in the sequence is not consecutive.
DENSE_RANK
The
DENSE_RANK
function acts like the
RANK
function except that it assigns consecutive ranks.
SELECT empno,
deptno,
sal,
DENSE_RANK() OVER (PARTITION BY deptno ORDER BY sal) "rank"
FROM emp;
EMPNO DEPTNO SAL rank
---------- ---------- ---------- ----------
7934 10 1300 1
7782 10 2450 2
7839 10 5000 3
7369 20 800 1
7876 20 1100 2
7566 20 2975 3
7788 20 3000 4
7902 20 3000 4
7900 30 950 1
7654 30 1250 2
7521 30 1250 2
7844 30 1500 3
7499 30 1600 4
7698 30 2850 5
FIRST and LAST
The
FIRST
and
LAST
functions can be used to
return the first or last value from an ordered sequence. Say we want to
display the salary of each employee, along with the lowest and highest
within their department we may use something like.
SELECT empno,
deptno,
sal,
MIN(sal) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) "Lowest",
MAX(sal) KEEP (DENSE_RANK LAST ORDER BY sal) OVER (PARTITION BY deptno) "Highest"
FROM emp
ORDER BY deptno, sal;
EMPNO DEPTNO SAL Lowest Highest
---------- ---------- ---------- ---------- ----------
7934 10 1300 1300 5000
7782 10 2450 1300 5000
7839 10 5000 1300 5000
7369 20 800 800 3000
7876 20 1100 800 3000
7566 20 2975 800 3000
7788 20 3000 800 3000
7902 20 3000 800 3000
7900 30 950 950 2850
7654 30 1250 950 2850
7521 30 1250 950 2850
7844 30 1500 950 2850
7499 30 1600 950 2850
7698 30 2850 950 2850
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